WebShow that 12n cannot end with the digit 0 or 5 for any natural number n. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3 ⇒ 12n = (22 × 3)n = 22n × 3n WebJul 17, 2014 · 25 n = (5 X 5) n If we raise 5 to any power ,unit digit will only be 5 . For any natural number to end with 0 , it must be a factor of 10 so it must have factors both 2 and 5 .But 25 does not have 2 as a factor. Thus 25 n cannot end with 0 for any natural number n Hope this would have cleared your doubt .

Ex 1.2, 5 - Check whether 6^n can end with digit 0 for any natural

WebAug 8, 2024 · Here `" " 12 = 2 xx 2 xx 3` `= 2^(2) xx 3` `rArr" " 12^(n) = (2^(2) xx 3)^(n) = 2^(2n) xx 3^(n)` We know that if any numbers ends with the digits 0 or 5, its is always divisible by 5. But the prime factorisation of `12^(n)` does not contain the prime number 5. Hence, `12^(n)` cannot end with the digits 0 or 5 for any natural number n. WebApr 21, 2024 · For a number to be end with digit zero its prime factors must have atleast one 2 and A are 5 both and for a number to be end with 5 its prime factors must have at least … pledge indian

Show that (12)n cannot end with digit 0 or 5 for any natural …

WebJan 18, 2024 · Step-by-step explanation: 12 to the power n cannot end with the digit 0 or 5 because for a number to end with the digit 0 or 5,it should have 2 and 5 both in its prime factorization. Here 12 to the power n= (2*2*3) to the power n, I. E it contains only 2 and not both 2 and 5 in its prime factorization. Please mark me as brainliest Advertisement WebGrievance procedure mor mortgage broker mentorship program/title ... WebJan 17, 2024 · Jan 16, 2024 125 Dislike Share Save Kwatra Tuition Center 18.4K subscribers 8. Show that 12n cannot end with the digit 0 or 5 for any natural number n. Search for #REALNUMBERSBYKTC For... prince parents ethnicity